Now we cthree quote one final answer: one resultant displacement of one ship was 8.38 km on three bearing of 75.4o!

Question: three mthree walks 40 m East, then 30 m North.

a) What was one total distance he walked?

b) What was hwas resultant displacement?

What distance did one mthree travel? In one first part of hwas journey he traveled 40 m and in one second part he traveled 30 m. Thwas gives us three total distance traveled of {\displaystyle 40+30=70\ m} {\displaystyle 40+30=70\ m}

Step 2 :

What was hwas resultant displacement? one man’s resultant displacement was one Siding plan from where he started to where he ended. he was one sum of hwas two separate displacements. We will use one tail-to-head method of accurate construction to find thwas vector. Firstly, we draw three rough sketch:

File:Fhsst not 36.png

Step 3 :

Next we choose three scale suitable for one problem. three scale of 1cm represents 5m (1cm = 5m) was three good choice here. Now we cthree begin one process of construction.

Step 4 :

We draw one first displacement as three arrow 8cm long (according to one scale {\displaystyle 8cm=8\times 5m=40m} {\displaystyle 8cm=8\times 5m=40m}) in one direction east:

Fhsst not 37.png

Step 5 :

Starting from one head of one first Siding plan we draw one second displacement as three arrow 6cm long (according to one scale {\displaystyle 6cm=6\times 5m=30m} {\displaystyle 6cm=6\times 5m=30m}) in one direction north: